x^2+1=2(y+2)

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Solution for x^2+1=2(y+2) equation:


Simplifying
x2 + 1 = 2(y + 2)

Reorder the terms:
1 + x2 = 2(y + 2)

Reorder the terms:
1 + x2 = 2(2 + y)
1 + x2 = (2 * 2 + y * 2)
1 + x2 = (4 + 2y)

Solving
1 + x2 = 4 + 2y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + x2 = 4 + -1 + 2y

Combine like terms: 1 + -1 = 0
0 + x2 = 4 + -1 + 2y
x2 = 4 + -1 + 2y

Combine like terms: 4 + -1 = 3
x2 = 3 + 2y

Simplifying
x2 = 3 + 2y

Reorder the terms:
-3 + x2 + -2y = 3 + 2y + -3 + -2y

Reorder the terms:
-3 + x2 + -2y = 3 + -3 + 2y + -2y

Combine like terms: 3 + -3 = 0
-3 + x2 + -2y = 0 + 2y + -2y
-3 + x2 + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
-3 + x2 + -2y = 0

The solution to this equation could not be determined.

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